//匿名内部类：
Runnable r = new Runnable() {
@Override
public void run() {
}
};
//改写成 lambda 表达式：
Runnable r = new Runnable(()->{});
无法通过编译，提示“'Runnable' is abstract; cannot be instantiated”
请问问题出在哪，非常感谢~This topic created in 1873 days ago, the information mentioned may be changed or developed.
 |
1
nthin0 Mar 26, 2021  1
Runnable r = () -> {};
|
 |
2
Ununennium OP @nthin0 谢谢大佬，但是为啥不用写 new runnable()啊
|
 |
3
ninjachen Mar 26, 2021
因为它不是 lambda 表达式
|
 |
4
brust Mar 27, 2021
Runnable r = ()->{};
Thread t = new Thread(new Runnable() { @Override public void run() { } }); Thread t = new Thread(()->{}); |
 |
5
zm8m93Q1e5otOC69 Mar 29, 2021
不用加 new 了吧 ()->{}就是 new 了
|
Select Language