wenjay
V2EX  ›  问与答

数组增删改判断

  •  
  •   wenjay · Jan 17, 2020 · 2014 views
    This topic created in 2326 days ago, the information mentioned may be changed or developed.

    交流个格式化函数format实现以下功能😃

    const oldData=[{ id: 1, name: '小明'},{ id: 2, name: '小直' },{ id: 3, name: '小信' }]
    const newData=[{ id: 1, name: '小明'},{ id: 2, name: '小奈' },{ id: 6, name: '小夜' }]
    
        format(oldData, newData)
    
    // {
    //   edit: [{ id: 2, name: '小奈' }],
    //   dele: [{ id: 3, name: '小信' }],
    //   add: [{ id: 6, name: '小夜' }],
    // }
    
    
    Supplement 1  ·  Jan 18, 2020

    场景描述:

    已知一个学生列表oldData,经过增删改后得到newData.
    最终对比得到以下三个数组:

    edit:被编辑的学生
    dele:被删除的学生
    add: 新增的学生

    2 replies    2020-01-19 09:55:33 +08:00
    kkkkkrua
        1
    kkkkkrua  
       Jan 17, 2020 via iPhone
    1 呢,直接说规则吧,不然还得玩找茬
    liuyx7894
        2
    liuyx7894  
       Jan 19, 2020
    直接上 diff 算法
    About   ·   Help   ·   Advertise   ·   Blog   ·   API   ·   FAQ   ·   Solana   ·   2699 Online   Highest 6679   ·     Select Language
    创意工作者们的社区
    World is powered by solitude
    VERSION: 3.9.8.5 · 30ms · UTC 12:19 · PVG 20:19 · LAX 05:19 · JFK 08:19
    ♥ Do have faith in what you're doing.