Python 有个小问题想请教下

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Mon Jul 09 17:35:26 +0800 2018 这种日期时间格式怎么转换成%Y-%m-%d %H-%M-%S 这种的呀,查了半天资料,没有转成功 233333

17:35:26

Python

Jul

Mon

17 replies • 2018-07-17 14:40:58 +08:00

blankme

Jul 17, 2018

https://docs.python.org/3/library/datetime.html#strftime-strptime-behavior
对着这个表格，转成 datetime object，然后重新输出

U87

Jul 17, 2018

@blankme 阿白真的很严格,2333

hlwjia

PRO

Jul 17, 2018

你的资料是怎么查的

U87

Jul 17, 2018

@hlwjia 就查百度啊

hlwjia

PRO

Jul 17, 2018

这种不是“方案”型的问题，就看文档就行了。

wqzjk393

Jul 17, 2018

time = 'Mon Jul 09 17:35:26 +0800 2018'
format1 = 'xxxxxxxx'
time_object = strptime(time,format1)
format2 = '%Y-%m-%d %H-%M-%S '
time = strftime(format2,time_object)

U87

Jul 17, 2018

@wqzjk393 time data "Mon Jul 09 17:35:26 +0800 2018" dose not match format "xxxxxxxx"

kkhu2004

Jul 17, 2018

s = 'Mon Jul 09 17:35:26 +0800 2018'
st = time.strptime(s, '%a %b %d %H:%M:%S %z %Y')
print(time.strftime('%Y-%m-%d %H-%M-%S', st))

U87

Jul 17, 2018

@hlwjia 好的下回知道,这种是查文档方便

U87

Jul 17, 2018

@kkhu2004 嗯嗯,这种很简单,查文档知道了

herozhang

Jul 17, 2018

用库 arrow

hubqin

Jul 17, 2018

```
import time
import datetime

text = 'Mon Jul 09 17:35:26 +0800 2018'

//将文本按对应格式转换成时间结构
timeStruct = time.strptime(text, '%a %b %d %X %z %Y')

//将时间结构转换成日期格式
time = time.strftime('%Y-%m-%d %H-%M-%S',timeStruct)

// result: 2018-07-09 17-35-26
print(time)

```