以下代码 main_swit
if kwarg.get('sub_switch'):
do()
del kwarg['sub_switch']
elif kwarg.get('sub_switch') is False:
del kwarg['sub_switch']
elif kwarg.get('sub_switch') is None and main_switch:
do()
这样的逻辑有没有可以优化的余地?
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This topic created in 3714 days ago, the information mentioned may be changed or developed.
6 replies • 2016-09-10 12:45:25 +08:00
 |
BOYPTSep 2, 2016
1
写到这样的逻辑都会想哭
|
 |
AllianzcortexSep 2, 2016
2
if 'sub_switch' in kwarg:
kwarg.pop() 这样子的。。。？？ |
 |
3
或许这样更好
```python try: if kwarg.pop('sub_switch'): do() except KeyError: if main_switch: do() ``` |
 |
just4testSep 5, 2016
4
首先你不能
temp = kwarg.get('sub_switch') 么？ |
|
6
果然抛开业务谈逻辑不是很好,这里还有个性能问题
查了一下,当 key 高概率在字典,可以用 try.否则先查看有没有,再执行逻辑,性能上会更好 |
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