已知ABC为三角, 边AB 长度为 w, AB和AC长度相等, BC长度为 n, A坐标(xA, yA), B坐标(xB, yB); 求C坐标(xC, yC)
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GordianZ Aug 19, 2010
画个图用勾股定理都能算出来，就这么点动手能力都没有？
http://en.wikipedia.org/wiki/Triangulation |
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badec Aug 19, 2010
呃，确实也有数学不好的人.
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utom OP (xa-xb)²+(ya-yb)²=w²
(xa-xc)²+(ya-yc)²=w² (xb-xc)²+(yb-yc)²=n² 求xc yc |
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6
explon Aug 19, 2010
无聊人士
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7
jiangxiaolei Aug 19, 2010
炫耀贴~
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