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请教php高手, 请问怎么catch fopen http request failed 这个error
itommy
·
May 4, 2011
· 4950 views
This topic created in 5475 days ago, the information mentioned may be changed or developed.
现在在用yahoo的api,那url有时好用有时不好用。现在fopen一failed,就全部用到那个相应variable的都error。
$url2 = "http://yahoo-url-here";
try {
$file2 = @
fopen
($url2, "r");
} catch(exception $e){
die('error');
}
$i=0;
while (!feof($file2)) {
//code here
$i++
}
programming菜鸟,随便写个了try catch在那,没用。
fopen
error
catch
2 replies
•
1970-01-01 08:00:00 +08:00
1
summic
May 4, 2011
这里已经写明了如何获取异常
http://developer.yahoo.com/php/howto-reqRestPhp.html
2
itommy
OP
May 5, 2011
@
summic
document还是要看的阿 我错了 谢谢! :)
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