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dict_a = {'a' : 1, 'b' : 2}
dict_b = {'a' : 2, 'b' : 3}
如何得到dict_c = {'a': 3, 'b': 5}
dict_b = {'a' : 2, 'b' : 3}
如何得到dict_c = {'a': 3, 'b': 5}
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lll9p Jul 24, 2014  1
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imn1 Jul 24, 2014
class collections.Counter([iterable-or-mapping])
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imn1 Jul 24, 2014
呃，求和，反应成计数了
统计方面的习惯都交给pandas了 |
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