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To be everywhere is to be nowhere. People who spend their whole life travelling abroad end up having plenty of places where they can find hospitality but no real friendships.
- Seneca. Letters from a Stoic (Classics S.) (p. 33). Penguin Books Ltd. Aug 11, 2021
- Seneca. Letters from a Stoic (Classics S.) (p. 33). Penguin Books Ltd. Aug 11, 2021
You should be extending your stay among writers whose genius is unquestionable, deriving constant nourishment from them if you wish to gain anything from your reading that will find a lasting place in your mind.
- Seneca. Letters from a Stoic (Classics S.) (p. 33). Penguin Books Ltd. Aug 11, 2021
- Seneca. Letters from a Stoic (Classics S.) (p. 33). Penguin Books Ltd. Aug 11, 2021
Nothing great comes into being all at once, for that is not the case even with a bunch of grapes or a fig.
- Epictetus. Discourses, Fragments, Handbook (Oxford World's Classics) . OUP Oxford. Aug 11, 2021
- Epictetus. Discourses, Fragments, Handbook (Oxford World's Classics) . OUP Oxford. Aug 11, 2021
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| 电信手机号验证不通过 程序员 • bigboNed3 • Mar 22, 2018 • Lastly replied by zzlhr | 9 |
bigboNed3's recent replies
Jan 28, 2023 Replied to a topic by jorneyr › 程序员 › Go 的范型怎么把 Response[指定类型] 转换为 Response[any] |
@jorneyr
```
// [4] 范型向上类型转换
// 相当于 Java 的范型用 ? 来接收任意类型的范型如
// List<String> list1 = new LinkedList<>();
// List<?> list2 = list1;
rsp3 := Response[any]{Code: rsp2.Code, Success: rsp2.Success, Data: rsp2.Data}
```
```
// [4] 范型向上类型转换
// 相当于 Java 的范型用 ? 来接收任意类型的范型如
// List<String> list1 = new LinkedList<>();
// List<?> list2 = list1;
rsp3 := Response[any]{Code: rsp2.Code, Success: rsp2.Success, Data: rsp2.Data}
```
Jun 24, 2020 Replied to a topic by naldo0193 › Python › 请问有快速和准确的汇总长短文相似文章的方法吗？ |
这个感觉最长公共子序列可以啊
return len(longest_common_subsequence(s)) > 0.7 * len(s)
return len(longest_common_subsequence(s)) > 0.7 * len(s)
Jun 24, 2020 Replied to a topic by firhome › 程序员 › 请教快速解析文本 html 的工具? |
python beautifulsoup
java jsoup
基本每个语言都会有对应的 soup
java jsoup
基本每个语言都会有对应的 soup
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