我也分享一段前辈的代码，哈哈

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List<HighxjRollVo> collect9 = highxjRollVoList.stream().filter(x -> x.getGradets().length() == 1 && gradelist.contains(x.getGradets())).filter(x -> !((Calendar.getInstance().get(Calendar.MONTH) + 1)-8 >0 ? ("20"+String.valueOf(Integer.valueOf(x.getHighStudentId().substring(0, 2))+Integer.valueOf(x.getGradets())-10)).equals(yearLast) : ("20"+String.valueOf(Integer.valueOf(x.getHighStudentId().substring(0, 2))+Integer.valueOf(x.getGradets())-10)).equals(beforeYearLast))).collect(Collectors.toList());

前辈写的，而且没有换行，全在一行里面
给我看的头疼，我都是让 gpt 帮我解释一下这行代码干了啥🤣

9 replies • 2023-06-21 11:02:58 +08:00

OutOfMemoryError

Jun 16, 2023

idea 一键格式化不就好了么这个项目的

hhjswf

Jun 16, 2023 via Android

咋一看像前端混淆的代码

PungentSauce

Jun 16, 2023

就俩过滤

chenPiMeiHaoChi

Jun 16, 2023

道理我都懂，但为什么是 collect9 ？想想还有 12345678 就更吓人了。

badbye

Jun 16, 2023

```
List<String> list = new ArryList<>();
for (int i = 0; i < strs.length; i++) {
if (list.contains(strs[i]))
continue;
list.add(strs[i]);
}
```
刚刚看到的代码

Nilus

Jun 16, 2023

@chenPiMeiHaoChi 哈哈看的好细总共 collect29🤣

yazinnnn

Jun 16, 2023

贴个刚写的烂代码

jasonjames

Jun 16, 2023

大佬囚牢囚牢
@haitaoli

Jarred711

Jun 21, 2023

In summary, the code filters a list of HighxjRollVo objects based on specific conditions using Java 8 Stream API. The resulting filtered elements are collected into a new list assigned to the collect9 variable.