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brucebot
V2EX  ›  Python

怎么样删除python list里面的","

  •  
  •   brucebot · 2013-08-31 05:49:21 +08:00 · 3145 次点击
    这是一个创建于 4104 天前的主题,其中的信息可能已经有所发展或是发生改变。
    比如有这么一段,想要删除",",这应该怎么来处理?

    [{"title": [["", " ", " Funny CAT = Funny cats in water, EPIC", " ", " ", " ", " Very Funny Cats!!", " ", " ", " ", " Cute Funny Cats Fail Compilation - 2013", " ", " ", " ", " 100 Funny Cats 2", " ", " ", " ", " Cats are terribly afraid of the water", " ", " ", " ", " NEW very funny cats!The Best!", " ", " ", " ", " The Best of funny and sweet Cats 2012 NEW", " ", " ", " ", " Funny Cats part 2 (WAR CATS!!)", " ", " ", " ", " Funny cats XD", " ", " ", " ", " Funny Cats Compilation (Hilarious)", " ", " ", " ", " 20 Minutes of Funny Cats!!!!", " ", " ", " ", " Funny Cats Compilation 2013 - Funny Cats Compilation", " ", " ", " ", " Funny Cats In Funny Cats Video When Toast Attacks", " ", " ", " ", " FUNNY ANIMALS VIDEO - FUNNY CATS STONED..", " ", " ", " ", " Funny Dogs & Cats Unusual - Ugly? Beauty is in the eye of the beholder.", " ", " ", " ", " Funny Cats Video Compilations-", " ", " ", " ", " Funny Cats. Little fail of Kitten", " ", " ", " ", " Funny CAT = Kitten miscalculates jump funny video cats", " ", " ", " ", " Funny Cats - Two kittens Playing with a Ball", " ", " ", " ", " Funny Cats Episode 1", " ", " "]]},
    第 1 条附言  ·  2013-08-31 09:06:45 +08:00
    我是用
    video['title'] = [''.join(app.select('./li/div/h3//text()').extract_unquoted()).split('\n')]

    在抓取网页头的时候得到这组数据的,如果不用split('\n')则会有很多个无用的\n,但是我又要保证每两个\n之间的字符串与其他的字符串分开,因为生成的是json,我需要与另一条命令

    video['link'] = app.select('./li/div/h3/a/@src').extract

    生成的json串对应起来
    5 条回复    1970-01-01 08:00:00 +08:00
    avichen
        1
    avichen  
       2013-08-31 06:22:42 +08:00
    list.remove(",")
    当然先要判断一下是否存在",",然后再remove。
    ahxxm
        2
    ahxxm  
       2013-08-31 06:22:53 +08:00 via Android
    [item for item in list if item != ","]
    9hills
        3
    9hills  
       2013-08-31 06:31:32 +08:00
    你们都没理解lz想要做什么,不是说list的内容里有',' , 而是lz想把list 打印出来,不含','。。

    Python list拼接推荐用join,很好理解
    String.join(list),就是将list的各个元素以字符串String(可以为空)拼接起来

    lz的例子显然是这样的
    ''.join(['sdfdsf','sdfsdf',' ', 'sdfdsf'])
    brucebot
        4
    brucebot  
    OP
       2013-08-31 08:17:17 +08:00
    我是用
    video['title'] = [''.join(app.select('./li/div/h3//text()').extract_unquoted()).split('\n')]

    在抓取网页头的时候得到这组数据的,如果不用split('\n')则会有很多个无用的\n,但是我又要保证每两个\n之间的字符串与其他的字符串分开,因为生成的是json,我需要与另一条命令

    video['link'] = app.select('./li/div/h3/a/@src').extract

    生成的json串对应起来



    @9hills
    @ahxxm
    @avichen
    detailyang
        5
    detailyang  
       2013-08-31 09:00:33 +08:00
    生成json最好用extract[0],不然json.loads会无法解析....同时记得判断数据是否存在,
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