推荐学习书目
› Learn Python the Hard Way
Python Sites
› PyPI - Python Package Index
› http://diveintopython.org/toc/index.html
› Pocoo
值得关注的项目
› PyPy
› Celery
› Jinja2
› Read the Docs
› gevent
› pyenv
› virtualenv
› Stackless Python
› Beautiful Soup
› 结巴中文分词
› Green Unicorn
› Sentry
› Shovel
› Pyflakes
› pytest
Python 编程
› pep8 Checker
Styles
› PEP 8
› Google Python Style Guide
› Code Style from The Hitchhiker's Guide
Python 如何生成今天 0 点到现在的所有以小时为单位的时间字符串？ and ...
Eyon · 2020-09-02 19:23:29 +08:00 · 2086 次点击这是一个创建于 1525 天前的主题，其中的信息可能已经有所发展或是发生改变。
需求：
get_today = [2020090200,2020090201,2020090202...2020090219]
get_month=[2020090100,2020090101,2020090102......2020090219]
get_today = [2020090200,2020090201,2020090202...2020090219]
get_month=[2020090100,2020090101,2020090102......2020090219]
 |
1
Trim21 2020-09-02 19:29:41 +08:00 via Android
用 datetime （ 0 点）循环加 timedelta （ hours=1 ），直到大于当前时间，然后把符合条件的的序列化成你想要的格式
|
 |
2
Eyon OP @Trim21 谢谢
```python from datetime import datetime,timedelta now = datetime.now() thismonth_start = now.strftime('%Y%m01') start = datetime(2020,9,1) while True: if start < now: print(start.strftime('%Y%m%d%H')) start = start+timedelta(hours=1) ``` |
 |
3
tairan2006 2020-09-02 23:16:22 +08:00 via Android
zfill 函数了解一下
|
 |
4
TEwrc 2020-09-03 16:37:32 +08:00
@tairan2006 看了一下没太懂 请教一下怎么用到题主说的这个问题上呢？
|
|
5
tairan2006 2020-09-03 17:31:25 +08:00
@TEwrc
now = datetime.now() prefix = now.strftime('%Y%m%d') return [prefix + str(x).zfill(2) for x in range(now.hour)] |
|
6
TEwrc 2020-09-04 12:00:52 +08:00
@tairan2006 秒啊！感谢
|
 |
7
biglazycat 2020-09-11 23:03:28 +08:00
from datetime import datetime
time_list = [] now = datetime.now() start_day_hour = int(now.strftime('%Y%m%d00')) stop_day_hour = int(now.strftime('%Y%m%d%H')) for i in range(start_day_hour, stop_day_hour + 1): time_list.append(i) print(time_list) |
Select Language