nilai
V2EX  ›  PHP

一个关于 PHP trim 函数的问题

  •  
  •   nilai · Jul 17, 2020 · 3749 views
    This topic created in 2151 days ago, the information mentioned may be changed or developed.
    代码非常简单:
    <?php
    $url='http://10.100.11.5/xapi.git';
    $tmp=trim($url,'.git');
    var_dump($tmp);
    $url='http://10.100.11.5/xapi';
    $tmp=trim($url,'git');
    var_dump($tmp);


    执行后的结果:
    root@debian10:/var/www/html# php 7.php
    string(22) "http://10.100.11.5/xap"
    string(22) "http://10.100.11.5/xap"
    问题:为什么会把字符串结尾的 i 字符给吞了,




    环境 php 7.3 php5.6 均测试如此
    19 replies    2020-07-20 09:38:09 +08:00
    geeglo
        1
    geeglo  
       Jul 17, 2020
    trim 的常见误区,的第二参数不会作为整体去移除。而是每个字符单独左右移除
    nilai
        2
    nilai  
    OP
       Jul 17, 2020
    @geeglo 若要整体移除呢? 用什么函数代替?
    zachlhb
        3
    zachlhb  
       Jul 17, 2020 via Android
    @nilai rtrim
    geeglo
        4
    geeglo  
       Jul 17, 2020
    没有,自己写。
    weirdo
        5
    weirdo  
       Jul 17, 2020   ❤️ 1
    @nilai str_replace preg_replace
    $url = str_replace('.git', '', $url)
    U7Q5tLAex2FI0o0g
        6
    U7Q5tLAex2FI0o0g  
       Jul 17, 2020
    手册有说明:
    https://www.php.net/manual/en/function.trim.php#refsect1-function.trim-notes

    Note: Possible gotcha: removing middle characters
    Because trim() trims characters from the beginning and end of a string, it may be confusing when characters are (or are not) removed from the middle. trim('abc', 'bad') removes both 'a' and 'b' because it trims 'a' thus moving 'b' to the beginning to also be trimmed. So, this is why it "works" whereas trim('abc', 'b') seemingly does not.
    rming
        7
    rming  
       Jul 17, 2020
    $url = 'http://10.100.11.5/xapi.git';
    $tmp = preg_replace("/\.git$/", "", $url);
    rming
        8
    rming  
       Jul 17, 2020
    preg_replace("/^start|end$/", "", "start content end")
    nilai
        9
    nilai  
    OP
       Jul 17, 2020
    @weirdo str_replace 不适合, str_replace 会替换字符串中的所有, trim 功能中只去头尾
    nilai
        10
    nilai  
    OP
       Jul 17, 2020
    @rming preg_replace 能实现。
    nilai
        11
    nilai  
    OP
       Jul 17, 2020
    @rming 简单写了个函数 这样可好?
    function strim($string,$removestring){
    if (!is_string($string) || !is_string($removestring)){
    return $string;
    }
    $result = preg_replace("/^{$removestring}|{$removestring}$/", "", $string);
    return $result;
    }
    nilai
        12
    nilai  
    OP
       Jul 17, 2020
    改成这样可能会更好点。
    function strim($string,$removestring=''){
    if (!is_string($string)){
    return $string;
    }
    if (!$removestring){
    return trim($string);
    }
    $result = preg_replace("/^{$removestring}|{$removestring}$/", "", $string);
    return $result;
    }
    KasuganoSoras
        13
    KasuganoSoras  
       Jul 17, 2020
    @nilai #9 不要忘了 str_replace 有 count 参数
    $url = str_replace(".git", "", $url, 1);
    这样就只会替换一次了,另外如果你只是想单纯去掉结尾 .git 的话
    $url = substr($url, -4, 4) == ".git" ? substr($url, 0, strlen($url) - 4) : $url;
    完事了
    airdge
        14
    airdge  
       Jul 17, 2020   ❤️ 2
    这不是很正常
    trim 会循环去除 charlist 里面的字符,直到完全移除
    igithttp://10.100.11.5/xapiggtigigit , git 这个应该也只会输出 http://10.100.11.5/xap
    yc8332
        15
    yc8332  
       Jul 17, 2020
    这个是去除字符,不是字符串。。。你要去除字符串要用替换
    WeKeey
        16
    WeKeey  
       Jul 17, 2020
    substr pathinfo
    jiehuangwei
        17
    jiehuangwei  
       Jul 17, 2020
    有意思,明显没细看函数吧 猜猜这个输出 啥 trim('abc', 'bad')
    sevenzhou1218
        18
    sevenzhou1218  
       Jul 17, 2020
    没仔细看手册,看了就不会问这个问题了
    cbasil
        19
    cbasil  
       Jul 20, 2020
    去除字符串用 str_replace 或者 preg_replace 啊,trim 一般用来去掉字符串二端的空格
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