V2EX = way to explore
V2EX 是一个关于分享和探索的地方
Sign Up Now
For Existing Member  Sign In
推荐学习书目
Learn Python the Hard Way
Python Sites
PyPI - Python Package Index
http://diveintopython.org/toc/index.html
Pocoo
值得关注的项目
PyPy
Celery
Jinja2
Read the Docs
gevent
pyenv
virtualenv
Stackless Python
Beautiful Soup
结巴中文分词
Green Unicorn
Sentry
Shovel
Pyflakes
pytest
Python 编程
pep8 Checker
Styles
PEP 8
Google Python Style Guide
Code Style from The Hitchhiker's Guide
Ewig
V2EX  ›  Python

xpath 拆分报错

  •  
  •   Ewig · Jan 10, 2019 · 1428 views
    This topic created in 2669 days ago, the information mentioned may be changed or developed.
    time_list = response.xpath('//div[@class="listBox"]/ul[@class="list"]//li/span/text()').extract()
    这个 xpath 我拆分成这样

    for item in response.xpath('//div[@class="listBox"]/ul[@class="list"]//li'):
    time=item.xpath('/span/text').extract()[0]
    title=item.xpath('/a/text()').extract()[0]
    link=item.xpath('/a/@href').extract()[0]
    print(time)
    print(title)
    print(link)

    我这样写的话会报错,如何写才是正确的?
    1 replies    2019-01-11 09:31:28 +08:00
    sikong31
        1
    sikong31  
       Jan 11, 2019
    time=item.xpath('/span/text').extract()[0]
    title=item.xpath('/a/text()').extract()[0]
    link=item.xpath('/a/@href').extract()[0]

    前面的 / 删掉就行了
    About   ·   Help   ·   Advertise   ·   Blog   ·   API   ·   FAQ   ·   Solana   ·   900 Online   Highest 6679   ·     Select Language
    创意工作者们的社区
    World is powered by solitude
    VERSION: 3.9.8.5 · 28ms · UTC 23:23 · PVG 07:23 · LAX 16:23 · JFK 19:23
    ♥ Do have faith in what you're doing.