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dlsea
V2EX  ›  Python

Python pdb.set_trace()问题

  •  
  •   dlsea · Dec 24, 2018 · 1906 views
    This topic created in 2695 days ago, the information mentioned may be changed or developed.
    代码很简单:
    import pdb
    def sum_nums(n):
    s = 0
    for i in range(n):
    pdb.set_trace()
    s += i
    print(s)
    if __name__ == '__main__':
    sum_nums(5)

    执行代码:
    > /root/1.py(7)sum_nums()
    -> s += i
    (Pdb) c
    0
    > /root/1.py(6)sum_nums()
    -> pdb.set_trace()
    (Pdb) c
    1
    > /root/1.py(7)sum_nums()
    -> s += i
    (Pdb) c
    3
    > /root/1.py(6)sum_nums()
    -> pdb.set_trace()
    (Pdb) c
    6
    > /root/1.py(7)sum_nums()
    -> s += i
    (Pdb) c
    10

    如果把代码改为:
    for i in range(n):
    s += i
    print(s)
    pdb.set_trace()
    那么执行后的每一条待执行都是-> for i in range(n):

    疑问:
    所有待执行的语句不应该都是 -> s += i 吗?为什么还穿插着 -> pdb.set_trace() ?
    4 replies    2018-12-25 20:20:22 +08:00
    hxse
        2
    hxse  
       Dec 24, 2018
    你贴的代码没有缩进, 看不懂你的意思
    dlsea
        3
    dlsea  
    OP
       Dec 25, 2018
    代码:
    import pdb

    def sum_nums(n):
    s = 0
    for i in range(n):
    pdb.set_trace()
    s += i
    print(s)
    if __name__ == '__main__':
    sum_nums(5)
    dlsea
        4
    dlsea  
    OP
       Dec 25, 2018
    重新输入上面的代码,空格自动被清除了
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