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wonder1z
V2EX  ›  Python

请教一个正则问题,懒惰匹配如何匹配多个内容

  •  
  •   wonder1z · Nov 22, 2018 · 2399 views
    This topic created in 2722 days ago, the information mentioned may be changed or developed.
    str = 'asd(hello)asd(world)'
    s = re.search(r'(?<=\().*?(?=\))',str1)
    print(s)
    
    <re.Match object; span=(4, 9), match='hello'>
    

    只能匹配出第一个 hello,如何匹配出所有()里的内容呢

    6 replies    2018-11-22 16:14:11 +08:00
    masker
        1
    masker  
       Nov 22, 2018 via Android
    \w+\((.*?)\){1,}
    sess222
        2
    sess222  
       Nov 22, 2018   ❤️ 1
    懒惰匹配是虾米?
    re.findall('\((.*?)\)', str1)
    wonder1z
        3
    wonder1z  
    OP
       Nov 22, 2018
    @masker 老铁 你这个不对啊
    wonder1z
        4
    wonder1z  
    OP
       Nov 22, 2018
    @sess222 这个也不对的,懒惰就是尽可能少的重复
    wonder1z
        5
    wonder1z  
    OP
       Nov 22, 2018
    @sess222 sorry 搞错了,你这个可以的
    Atukey
        6
    Atukey  
       Nov 22, 2018
    (?<=\()\w*(?=\))
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