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lancerly
V2EX  ›  Linux

看 Xposed 的时候发现一条奇怪的 shell 命令,结构是 filepath 2 1 filepath 有点不解,求会的人帮我解释下

  •  
  •   lancerly · Sep 21, 2018 · 2853 views
    This topic created in 2791 days ago, the information mentioned may be changed or developed.

    源代码:

    int result = rootUtil.execute(getShellPath(updateBinaryFile) + " 2 1 " + getShellPath(mZipPath), callback);
    
        public synchronized int execute(String command, LineCallback callback) {
            if (mShell == null) {
                throw new IllegalStateException("shell is not running");
            }
    
            mCallback = callback;
            mCommandRunning = true;
            mShell.addCommand(command, 0, mStdoutListener);
            waitForCommandFinished();
    
            return mLastExitCode;
        }
        
            public synchronized void addCommand(String[] commands, int code,
                                                OnCommandLineListener onCommandLineListener) {
                this.commands.add(new Command(commands, code, null, onCommandLineListener));
                runNextCommand();
            }
    

    参数代入后的命令是:

    /data/data/de.robv.android.xposed.installer/cache/update-binary 2 1 /storage/emulated/0/Android/data/de.robv.android.xposed.installer/cache/downloads/framework/xposed-v89-sdk24-arm64.zip
    

    可以看到执行的就是上面那条命令, 求解,这个命令是啥?

    3 replies    2018-09-21 18:34:44 +08:00
    omph
        1
    omph  
       Sep 21, 2018   ❤️ 1
    update-binary 是 shell 脚本,后面带了三个参数,有什么问题?
    ysc3839
        2
    ysc3839  
       Sep 21, 2018 via Android
    看 update-binary 的代码。
    lancerly
        3
    lancerly  
    OP
       Sep 21, 2018
    @omph 哦哦,我懂了...我脑子瓦特了,,,
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