bash 的多行变量传递问题

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#!/bin/bash            #1
read -d '' sql << EOF  #2
select c1, c2 from foo
where c1='something'
EOF
echo "$sql"            #6
export sql             #7
bash -c 'echo $sql'    #8

为什么第 6 行能正确输出多行变量，第 8 行就合并成单行了呢？

2 replies • 2018-01-10 05:01:27 +08:00

ytterbium

Jan 10, 2018 via Android

双引号

param

Jan 10, 2018

@ytterbium 咦！神奇。居然是这种错误。。知道问题了。。谢谢