请教一个字符串截取问题

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This topic created in 3357 days ago, the information mentioned may be changed or developed.

例如 url ：
xxx/xxx-102.html
xxx/xxx-43.html

想通过"-"以及"."去定位中字符串并存入列表.
请问如何实现?

字符

XXX

URL

截取

10 replies • 2017-02-16 17:33:35 +08:00

okletswin

Feb 15, 2017

re.match(r'.*-([^\.]+)\.', 'xxx-102.html')

fei051466

Feb 15, 2017

>>> target = 'xxx/xxx-102.html'
>>> result = target[target.find('-') + 1: target.find('.')]
>>> result
'102'

leavic

Feb 15, 2017 via iPhone

不想用 re 就做两次 split

zhicheng

Feb 15, 2017

>>> 'xxx/xxx-102.html'.rpartition('-')[2].partition('.')[0]
'102'
>>> 'xxx/xxx-43.html'.rpartition('-')[2].partition('.')[0]
'43'
>>> ''.rpartition('-')[2].partition('.')[0]
''
>>> '-------------'.rpartition('-')[2].partition('.')[0]
''
>>> '.........'.rpartition('-')[2].partition('.')[0]
''
>>> '-.-.-.-.-.-.'.rpartition('-')[2].partition('.')[0]
''
>>> '-123.-456.-789.-123.-456.-789.'.rpartition('-')[2].partition('.')[0]
'789'
>>> 'laksdjflkajs8923u41--..asdf92u34100---12342.'.rpartition('-')[2].partition('.')[0]
'12342'