问题:怎么用 php ,把数据从 mysql 中取出来,然后送给 javascript ?以前没搞过,求指导。
目的:数据库中的数据,通过 AwesomeChartJS 画图
具体描述:下面是 AwesomeChartJS 给的例子,我需要从 mysql 中取数据,然后替换 mychart.data 和 mychart.labels 的数据。
<script type="application/javascript" src="awesomechart.js"></script>
<script type="application/javascript">
function drawMyChart(){
if(!!document.createElement('canvas').getContext){ //check that the canvas
// element is supported
var mychart = new AwesomeChart('canvas1');
mychart.title = "Product Sales - 2010";
mychart.data = [1532, 3251, 3460, 1180, 6543];
mychart.labels = ["Desktops", "Laptops", "Netbooks", "Tablets", "Smartphones"];
mychart.draw();
}
}
window. onload = drawMyChart;
</script>
目的:数据库中的数据,通过 AwesomeChartJS 画图
具体描述:下面是 AwesomeChartJS 给的例子,我需要从 mysql 中取数据,然后替换 mychart.data 和 mychart.labels 的数据。
<script type="application/javascript" src="awesomechart.js"></script>
<script type="application/javascript">
function drawMyChart(){
if(!!document.createElement('canvas').getContext){ //check that the canvas
// element is supported
var mychart = new AwesomeChart('canvas1');
mychart.title = "Product Sales - 2010";
mychart.data = [1532, 3251, 3460, 1180, 6543];
mychart.labels = ["Desktops", "Laptops", "Netbooks", "Tablets", "Smartphones"];
mychart.draw();
}
}
window. onload = drawMyChart;
</script>