zebulon

我尝试用 for 循环来简化这个却只能出现最后计算的数值,有没有办法能简化这段代码

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  •   zebulon · Dec 23, 2015 · 2633 views
    This topic created in 3794 days ago, the information mentioned may be changed or developed.

    $(".job-level .ce_text a:eq(0)").attr("href","#tab1");
    $(".job-level .ce_text a:eq(1)").attr("href","#tab2");
    $(".job-level .ce_text a:eq(2)").attr("href","#tab3");
    $(".job-level .ce_text a:eq(3)").attr("href","#tab4");
    $(".job-level .ce_text a:eq(4)").attr("href","#tab5");
    $(".job-level .ce_text a:eq(5)").attr("href","#tab6");
    $(".job-level .ce_text a:eq(6)").attr("href","#tab7");
    $(".job-level .ce_text a:eq(7)").attr("href","#tab8");
    $(".job-level .ce_text a:eq(8)").attr("href","#tab9");
    $(".job-level .ce_text a:eq(9)").attr("href","#tab10");
    $(".job-level .ce_text a:eq(10)").attr("href","#tab11");
    $(".job-level .ce_text a:eq(11)").attr("href","#tab12");
    $(".job-level .ce_text a:eq(12)").attr("href","#tab13");
    $(".job-level .ce_text a:eq(13)").attr("href","#tab14");
    $(".job-level .ce_text a:eq(14)").attr("href","#tab15");

    5 replies    2015-12-23 21:21:03 +08:00
    denghongcai
        1
    denghongcai  
       Dec 23, 2015
    为什么 for 不行? attr 是同步阻塞函数,不会出现在 for 里使用异步函数常见问题
    aliuwr
        2
    aliuwr  
       Dec 23, 2015   ❤️ 1
    $(".job-level .ce_text a").each(function(i, e) { e.href = '#tab' + (i + 1);});
    zebulon
        3
    zebulon  
    OP
       Dec 23, 2015
    @aliuwr 太感谢了
    zebulon
        4
    zebulon  
    OP
       Dec 23, 2015
    @denghongcai 也许是我写的不对吧
    hronro
        5
    hronro  
       Dec 23, 2015
    JS 没有块级作用域的问题,到 ES6 中可以用 let 解决
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