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这是一个创建于 1838 天前的主题，其中的信息可能已经有所发展或是发生改变。
文本内容:
network-object host 109.17.49.131
object-group network KaGuan_12
network-object host 109.17.26.11
network-object host 109.17.26.12
object-group network ShangHai
network-object host 110.1.60.91
network-object host 110.1.60.92
network-object host 110.1.172.31
network-object host 110.1.172.32
network-object host 110.238.250.57
network-object host 110.238.250.58
object-group network wangguan_test
network-object host 111.17.13.32
object-group network wangguan_app_2
network-object host 111.17.9.54
network-object host 111.17.9.63
我现在想通过 110.1.172.32 这个字符串 匹配到 object-group network 后面的 ShangHai 这个关键词, 请问正则怎么写? 感谢各位大佬
12 条回复 • 2019-11-15 09:43:43 +08:00
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1
lululau 2019-11-14 08:52:05 +08:00 via iPhone
正则正则，起码把规则说出来啊，你只举一个特例，那你直接把这个特例写成字符串字面量就可以了，不需要正则啊，再说，你这个说的 110.1.172.32 后面也没有 shanghai 啊
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2
TOUJOURSER OP @lululau 不好意思描述的不太清楚, 规则是根据 ip 去获取该 ip 所属于的 group.
我想通过 110.1.172.32 去向上查找以"object-group network "开头的那一行最后的 ShangHai 字符. |
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3
araraloren 2019-11-14 09:03:58 +08:00
自己字符串直接查找不行么，如果是在练习正则的话当我没说。。
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4
ClericPy 2019-11-14 09:11:13 +08:00
import re
string = r'''network-object host 109.17.49.131 object-group network KaGuan_12 network-object host 109.17.26.11 network-object host 109.17.26.12 object-group network ShangHai network-object host 110.1.60.91 network-object host 110.1.60.92 network-object host 110.1.172.31 network-object host 110.1.172.32 network-object host 110.238.250.57 network-object host 110.238.250.58 object-group network wangguan_test network-object host 111.17.13.32 object-group network wangguan_app_2 network-object host 111.17.9.54 network-object host 111.17.9.63''' ip = '110.1.172.32'.replace('.', r'\.') result = re.search( rf'object-group network (.*?)\n[\s\S]*?network-object host {ip}', string) if result: print(result.group(1)) else: print('Not found.') KaGuan_12 |
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5
TOUJOURSER OP @ClericPy 感谢, 你写的这个只可以匹配出 KaGuan_12 , 但是我需要的是 ShangHai, 110.1.172.32 是属于 ShangHai group
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6
todd7zhang 2019-11-14 09:30:24 +08:00  2
import re
a = ''' network-object host 109.17.49.131 object-group network KaGuan_12 network-object host 109.17.26.11 network-object host 109.17.26.12 object-group network ShangHai network-object host 110.1.60.91 network-object host 110.1.60.92 network-object host 110.1.172.31 network-object host 110.1.172.32 network-object host 110.238.250.57 network-object host 110.238.250.58 object-group network wangguan_test network-object host 111.17.13.32 object-group network wangguan_app_2 network-object host 111.17.9.54 network-object host 111.17.9.63 ''' re.findall(r'object-group network (\w+)(?:(?:(?!object-group).)*)(?=network-object host 110\.1\.172\.31)', a, re.DOTALL) |
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7
ClericPy 2019-11-14 09:33:15 +08:00
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8
ClericPy 2019-11-14 09:34:12 +08:00 1
6 楼的零宽断言是个好方法, 先匹配非 group 再取 group
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9
TOUJOURSER OP @ClericPy @todd7zhang 真的非常感谢, 这个问题困扰了我好久
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10
qingshengwen 2019-11-14 12:07:55 +08:00
试试这个看看
object\-group\snetwork\s(.*?)(?:\s*network\-object\shost\s\d+\.\d+\.\d+\.\d+\s*){0,}(?:\s*network\-object\shost\s110.1.172.32\s*) https://imgur.com/a/loDyJo7 |
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11
no1xsyzy 2019-11-14 19:39:32 +08:00
写个 FSM 不行吗？这还正则？（不超过十分钟写完）
https://gist.github.com/no1xsyzy/11ba23cd13f90b3f94227d4838fd7e5a |
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12
corningsun 2019-11-15 09:43:43 +08:00
用不上正则
如果只需要一次匹配，只是两次截取字符串的问题，代码示例如下： https://gist.github.com/corningsun/87aac1ca2bc46e698a4d332a93118bbe 如果需要多次匹配，且数据量不大的话，最好的还是解析所有 IP，做哈希表查找比较好。 |
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