@awaitjs/express 怎么能够在 res.json()后继续完成一个长时间的任务

我看到别人的提问里面

var express = require('express');
var app = express();

app.get('/some/route', (req, res)=> {
  res.json({success: false, message: "End time must be AFTER start time"});
  console.log('Hi')
});

这个 console.log('Hi')会被执行。现在我有一个需求，要用 @awaitjs/express 来 decorate express，代码大概如下

const express = require('express');
const { decorateApp } = require('@awaitjs/express');
const app = decorateApp(express());
const port = 3000;

function sleep(ms) {
  return new Promise(resolve => setTimeout(resolve, ms));
}

app.getAsync('/toggle', async function(req, res){
        let period = parseInt(req.query.period);
        let count = parseInt(req.query.count);
        
        res.json({success: true, message: "Power cycle schedueled successfuly for the interval of " + req.query.period + " minute(s), totaling " + req.query.count + " times."});
        while(count-- > 0){           
               await do_something();
        }
        
        
    });
await app.listen(port, () => console.log(`Example app listening on port ${port}!`))

这个 res.json 后面的 while loop 是一个长时间执行的代码。我期望的是如前面第一个例子那样，在 res.json 返回客户端一个结果后继续执行 while loop。但是实际上这个 while loop 并不会运行，我哪里做的不对？